Questions on gay lussacs law of combining volume

Explanation

(a) Gay - Lussac Regulation of combining volumes states that when gases react, they do so in volumes which are in simple ratios to one another and to the volume of the product, if gaseous, provided that the temperature and pressure remain constant.

(b) 2H\(_2\) + O\(_2\) -> 2H\(_2\)O. According to the equation, 2 volume of H\(_2\) requires 1 volume of oxygen.

50cm\(^3\) of H\(_2\) requires 25cm\(^3\) of oxygen,

volume of oxygen available = 30cm\(^3\),

volume of unused oxygen 30 - 25 = 5cm\(^3\).

Gay-Lussac's Law
Problems #1 - 10

Ten Examples

KMT & Gas Laws Menu

Problem #1: A L sample of nitrogen inside a rigid, metal container at &#;C is placed inside an oven whose temperature is &#;C. The pressure inside the container at &#;C was at atm. What is the pressure of the nitrogen after its temperature is increased to &#;C?

Solution:

P1		P2
–––	=	–––
T1		T2

		x
–––	=	–––

Solution technique: cross-multiply and distribute.

x = atm (to three sig figs)

Note: you will see set ups (especially in gas laws) that simply omit all the units in the solution. If you complete that on a homework problem or test, you may get a deduction. It's not laziness on the part of the person writing the answer, it's simply assuming the reader knows what the units are and how they cancel out to leave the final unit.

Many times, you (as the student) are not allowed that luxury.

Problem #2: Determine the pressure change when a continual volume of gas at atm is heated from &#;C to &#;C.

Solution:

P₁ / T₁ = P₂ / T₂

atm / = x

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Gay Lussac’s Law of Combining Volumes

 

Gay Lussac’s Law of Combining Volumes states that when gases react, they do so in volumes which bear a simple ratio to one another, and to the volume of the product(s) formed if gaseous, provided the temperature and pressure remain constant.

The rule explains experimental facts about how gaseous atoms combine. Example:

For the reactions:

(i) N_2(g) + 3H_2(g) → 2NH_3(g)

   1 vol.    3 vols.    2 vols.

1 volume of nitrogen combines with 3 volumes of hydrogen to form 2 volumes of ammonia.

(ii) 2H_2(g) + O_2(g) → 2H₂O_(g)

     2 vols.   1 vol.     2 vols.

2 volumes of hydrogen combine with 1 volume of oxygen to form 2 volumes of steam.

(iii) Cl_2(g) + H_2(g) → 2HCl_(g)

     1 vol.    1 vol.    2 vols.

1 volume of chlorine gas combines with 1 volume of hydrogen to form 2 volumes of hydrochloric acid.

Question: Consider the reaction: 2H_2(g) + O_2(g) → 2H₂O_(g)

(a). What volume of steam is formed from 20 cm³ of hydrogen and 20 cm³ of oxygen mixed

.